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(D) Given equations:$0.5x + 0.3y - 0.1 = 0$  --- $(1)$$0.6x + 0.3y - 0.3 = 0$  --- $(2)$Multiply both equations by $10$ to simplify:$5x + 3y - 1 = 0$$

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$(2, -3)$

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(D) Given equations:$0.5x + 0.3y - 0.1 = 0$  --- $(1)$$0.6x + 0.3y - 0.3 = 0$  --- $(2)$Multiply both equations by $10$ to simplify:$5x + 3y - 1 = 0$$6x + 3y - 3 = 0$Using the cross-multiplication formula for $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:$\frac{x}{b_1c_2 - b_2c_1} = \frac{y}{c_1a_2 - c_2a_1} = \frac{1}{a_1b_2 - a_2b_1}$Here,$a_1 = 5, b_1 = 3, c_1 = -1$ and $a_2 = 6, b_2 = 3, c_2 = -3$.$\frac{x}{(3)(-3) - (3)(-1)} = \frac{y}{(-1)(6) - (-3)(5)} = \frac{1}{(5)(3) - (6)(3)}$$\frac{x}{-9 + 3} = \frac{y}{-6 + 15} = \frac{1}{15 - 18}$$\frac{x}{-6} = \frac{y}{9} = \frac{1}{-3}$$x = \frac{-6}{-3} = 2$$y = \frac{9}{-3} = -3$Thus,the solution is $(2, -3)$.

Solve the following pairs of equations by the cross-multiplication method:
$0.5x + 0.3y = 0.1$
$0.6x + 0.3y = 0.3$

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Solve the following pairs of equations by the cross-multiplication method:$0.5x + 0.3y = 0.1$$0.6x + 0.3y = 0.3$